Quantitative Aptitude Questions and Answers With Explanation (Practice set 12)

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Q1:
The speed of a car increases by 2 km after every one hour. If the distance traveling in the first one hour was 35 km. what was the total distance traveled in 12 hours?

A) 456 kms B) 482 kms
C) 552 kms D) 556 km

Q2:
If 7 spiders make 7 webs in 7 days, then 1 spider will make 1 web in how many days?

A) 1 B) 3
C) 7 D) 14

Q3:
Find the compound interest on Rs. 8000 at 15% per annum for 2 years 4 months, compounded annually

A) 2109 B) 3109
C) 4109 D) 6109

Q4:
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:

A) 123 B) 127
C) 235 D) 305

Q5:
In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :

A) 19 B) 29
C) 39 D) 49

Q6:
Gaurav spends 30% of his monthly income on food articles, 40% of the remaining on conveyance and clothes, and saves 50% of the remaining. If his monthly salary is Rs. 18,400, how much money does he save every month?

A) 3864 B) 4903
C) 5849 D) 6789

Q7:
What was the day of the week on 17th June 1998?

A) Monday B) Tuesday
C) Wednesday D) Friday

Q8:
In an election only two candidates contested 20% of the voters did not vote and 120 votes were declared as invalid. The winner got 200 votes more than his opponent thus he secured 41% votes of the total voters on the voter list. Percentage votes of the defeated candidate out of the total votes cast is:

A) 47.5% B) 41%
C) 38% D) 45%

Q9:
The mean of 50 observations was 36. It was found later that an observation 48 was wrongly taken as 23. The corrected new mean is :

A) 35 B) 36.5
C) 40 D) 42

Q10:
The ratio of two numbers is 3:4 and their H.C.F is 4. Their L.C.M is 

A) 12 B) 16
C) 24 D) 48


ANSWERS WITH EXPLANATION

 

Answer1: C) 552 km
Explanation:
Total distance travelled in 12 hours    =(35+37+39+.....upto 12 terms)
This is an A.P with first term, a=35, number of terms,
n= 12,d=2.
Required distance    = 12/2[2 x 35+{12-1) x 2]
=6(70+23)
= 552 kms.

Answer2: C) 7
Explanation:
Let the required number of days be x.
Fewer spiders, More days (Indirect Proportion)
Fewer webs, Fewer days (Direct Proportion)
Spiders 1:7 ----------------(1)
Webs 7:1-------------------(2)
From (1) and (2), we have
7:x
=> 1 * 7 * x = 7 * 1 * 7 
=> x= 7

Answer3: B) 3109
Explanation:
Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.
Amount = Rs'. [8000 X (1+(15/100))^2 X (1+((1/3)*15)/100)]
=Rs. [8000 * (23/20) * (23/20) * (21/20)]
= Rs. 11109. .
:. C.I. = Rs. (11109 - 8000) = Rs. 3109.

Answer4: B) 127
Explanation:
Required number = H.C.F. of (1657 - 6) and (2037 - 5)
= H.C.F. of 1651 and 2032 = 127.

Answer5: C) 39
Explanation:
Let B's present age = x years. Then, A's present age = (x + 9) years.
(x + 9) + 10 = 2(x - 10)
 => x + 19 = 2x - 20
 => x =39.

Answer6: A) 3864
Explanation:
Saving  = 50% of (100 - 40)% of (100 - 30)% of Rs. 18,400 = Rs. (50/100 * 60/100 * 70/100 * 18400) = Rs. 3864.

Answer7: C) Wednesday
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March. April. May. June.
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
The given day is Wednesday.

     

Answer8: D) 45%
Explanation:
Let there be x voters and k votes goes to loser then 
      0.8x - 120 = k + (k + 200)
        k+200 = 0.41x
 => k = 1440
and  (k + 200) =1640
Therefore  1440/3200 x 100 = 45%

Answer9: B) 36.5
Explanation:
Correct Sum = (36 * 50 + 48 - 23) = 1825.
Correct mean = = 1825/50 = 36.5

Answer10: D) 48
Explanation:
Let the numbers be  3x and 4x. Then their H.C.F = x. So, x=4
Therefore, The numbers are 12 and 16
L.C.M of 12 and 16 = 48

 

Also Practice: Quantitative Aptitude Questions and Answers With Explanation (Practice set 11)

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