Quantitative Aptitude Questions and Answers With Explanation (Practice set 15)

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Q1:
L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

A) -2 B) -1
C) 1 D) 2

Q2:
A sum of Rs. 427 is to be divided among A, B, and C such that 3 times A’s share, 4 tunes B’s share, and 7 times C’s share are all equal. The share of C is :

A) 84 B) 140
C) 196 D) 240

Q3:
What annual installment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

A) Rs.325 B) Rs.545
C) Rs.560 D) Rs.550

Q4:
How much time will take for an amount of Rs 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?

A) 4 years B) 2.5 years
C) 3.5 years D) 2 years

Q5:
What is the place value of 6 in 64?

A) 6 B) 60
C) 64 D) 10

Q6:
The salaries of A, B, and C are in the ratio of 1: 2 : 3. The salary of B and C together is Rs. 6000. By what percent is the salary of C more than that of A?

A) 100 % B) 200%
C) 300% D) 600%

Q7:
In a box, there are 8 red, 7 blue, and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

A) 1/3 B) 3/5
C) 8/21 D) 7/21

Q8:
Insert the missing number.
3, 7, 6, 5, 9, 3, 12, 1, 15, (....)

A) 18 B) 13
C) -1 D) 3

Q9:
A rectangular block 6 cm by 12 cm by 15 cm is cut up into an exact number of equal cubes. Find the least possible number of cubes.

A) 30 B) 40
C) 10 D) 20

Q10:
The product of the two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is 

A) 101 B) 107
C) 111 D) 185


ANSWERS WITH EXPLANATION

 

Answer1: A) -2
Explanation:

H. C. F of two prime numbers is 1.  Product of numbers = 1 x 161 = 161.

Let the numbers be a and b. Then, ab= 161.
Now, co-primes with product 161 are (1, 161) and (7, 23).
Since x and y are prime numbers and x >y, we have x=23 and y=7.
Therefore,  3y-x = (3 x 7)-23 = -2

Answer2: A) 84
Explanation:

3A = 4B = 7C = k,Then A = k/3, B = k/4 and C= k/7.
A : B : C = k/3 : k/4 : k/7 = 28:21 :12.
Cs share = Rs. [427 x (12/61)] = Rs. 84

Answer3: A) Rs.325
Explanation:

Let each installment be Rs.x.
1st year =  [x + (x * 12 * 2)/100] 
2nd year = [ x + (x *12 * 1)/100] 
3rd year = x 
Then, [x + (x * 12 * 2)/100] + [ x + (x *12 * 1)/100] + x =1092 
3x + ( 24x/100 ) + ( 12x/100 )  = 1092 
336x =109200
Therefore, x = 325 
Each instalment = Rs. 325

Answer4: A) 4 years
Explanation:

Time = (100 x 81) / (450 x 4.5) = 4 years.

Answer5: B) 60
Explanation:

We know that,
● Each digit has a fixed position called its place.
● Each digit has a value depending on its place called the place value of the digit.
● The face value of a digit for any place in the given number is the value of the digit itself
● Place Value of a digit = (face value of the digit) × (value of the place).
Hence, the place value of 6 in 64 = 6 x 10 = 60.

Answer6: B) 200%
Explanation:

Let the salaries of A, B, C be x, 2x and 3x respectively.
Then,2x + 3x = 6000  => x = 1200.
A's salary = Rs. 1200, B's salary = Rs. 2400, and Cs salary Rs. 3600.
Excess of C's salary over A's=[ (2400 /1200) x 100] = 200%.

Answer7: A) 1/3
Explanation:

Total number of balls = (8 + 7 + 6) = 21.
Let E = event that the ball drawn is neither red nor green 
            = event that the ball is drawn is blue.
n(E) = 7.
P(E) = n(E)/n(S) = 7/21 = 1/3.

Answer8: C) -1
Explanation:

There are two series, beginning respectively with 3 and 7. In one 3 is added and in another 2 is subtracted.
The next number is 1 - 2 = -1.

Answer9: B) 40
Explanation:

Volume of the block = (6 x 12 x 15) cu.cm = 1080 cu.cm 
Side of the largest cube = H.C.F. of 6 cm, 12 cm, 15 cm 
                                   = 3 cm.
Volume of this cube  = (3 x 3 x 3) cu.cm = 27 cu.cm 
Number of cubes =1080/27 = 40.

Answer10: C) 111
Explanation:

 Let the numbers be 37a and 37b. Then , 37a x 37b =4107  => ab = 3.
 Now co-primes with product 3 are (1,3)
 So, the required numbers are (37 x 1, 37 x 3) i.e, (37,111).
 Therefore, Greater number = 111.

Also Practice: 

Quantitative Aptitude Questions and Answers With Explanation (Practice set 14)

 

 

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