## Quantitative Aptitude Questions and Answers With Explanation (Practice set 15)

By Sahil Bansal | Views: 996

Q1:
L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

A) -2 B) -1
C) 1 D) 2

Q2:
A sum of Rs. 427 is to be divided among A, B, and C such that 3 times A’s share, 4 tunes B’s share, and 7 times C’s share are all equal. The share of C is :

A) 84 B) 140
C) 196 D) 240

Q3:
What annual installment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

A) Rs.325 B) Rs.545
C) Rs.560 D) Rs.550

Q4:
How much time will take for an amount of Rs 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?

A) 4 years B) 2.5 years
C) 3.5 years D) 2 years

Q5:
What is the place value of 6 in 64?

A) 6 B) 60
C) 64 D) 10

Q6:
The salaries of A, B, and C are in the ratio of 1: 2 : 3. The salary of B and C together is Rs. 6000. By what percent is the salary of C more than that of A?

A) 100 % B) 200%
C) 300% D) 600%

Q7:
In a box, there are 8 red, 7 blue, and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

A) 1/3 B) 3/5
C) 8/21 D) 7/21

Q8:
Insert the missing number.
3, 7, 6, 5, 9, 3, 12, 1, 15, (....)

A) 18 B) 13
C) -1 D) 3

Q9:
A rectangular block 6 cm by 12 cm by 15 cm is cut up into an exact number of equal cubes. Find the least possible number of cubes.

A) 30 B) 40
C) 10 D) 20

Q10:
The product of the two numbers is 4107. If the H.C.F of these numbers is 37, then the greater number is

A) 101 B) 107
C) 111 D) 185

Explanation:

H. C. F of two prime numbers is 1.  Product of numbers = 1 x 161 = 161.

Let the numbers be a and b. Then, ab= 161.
Now, co-primes with product 161 are (1, 161) and (7, 23).
Since x and y are prime numbers and x >y, we have x=23 and y=7.
Therefore,  3y-x = (3 x 7)-23 = -2

Explanation:

3A = 4B = 7C = k,Then A = k/3, B = k/4 and C= k/7.
A : B : C = k/3 : k/4 : k/7 = 28:21 :12.
Cs share = Rs. [427 x (12/61)] = Rs. 84

Explanation:

Let each installment be Rs.x.
1st year =  [x + (x * 12 * 2)/100]
2nd year = [ x + (x *12 * 1)/100]
3rd year = x
Then, [x + (x * 12 * 2)/100] + [ x + (x *12 * 1)/100] + x =1092
3x + ( 24x/100 ) + ( 12x/100 )  = 1092
336x =109200
Therefore, x = 325
Each instalment = Rs. 325

Explanation:

Time = (100 x 81) / (450 x 4.5) = 4 years.

Explanation:

We know that,
● Each digit has a fixed position called its place.
● Each digit has a value depending on its place called the place value of the digit.
● The face value of a digit for any place in the given number is the value of the digit itself
● Place Value of a digit = (face value of the digit) × (value of the place).
Hence, the place value of 6 in 64 = 6 x 10 = 60.

Explanation:

Let the salaries of A, B, C be x, 2x and 3x respectively.
Then,2x + 3x = 6000  => x = 1200.
A's salary = Rs. 1200, B's salary = Rs. 2400, and Cs salary Rs. 3600.
Excess of C's salary over A's=[ (2400 /1200) x 100] = 200%.

Explanation:

Total number of balls = (8 + 7 + 6) = 21.
Let E = event that the ball drawn is neither red nor green
= event that the ball is drawn is blue.
n(E) = 7.
P(E) = n(E)/n(S) = 7/21 = 1/3.

Explanation:

There are two series, beginning respectively with 3 and 7. In one 3 is added and in another 2 is subtracted.
The next number is 1 - 2 = -1.

Explanation:

Volume of the block = (6 x 12 x 15) cu.cm = 1080 cu.cm
Side of the largest cube = H.C.F. of 6 cm, 12 cm, 15 cm
= 3 cm.
Volume of this cube  = (3 x 3 x 3) cu.cm = 27 cu.cm
Number of cubes =1080/27 = 40.

Explanation:

Let the numbers be 37a and 37b. Then , 37a x 37b =4107  => ab = 3.
Now co-primes with product 3 are (1,3)
So, the required numbers are (37 x 1, 37 x 3) i.e, (37,111).
Therefore, Greater number = 111.

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