Q1:
A and B started a business jointly A's investment was thrice the investment of B and the period of his investment was two times the period of investment of B. If B received Rs. 4000 as profit, then their total profit is :

A) 22000 B) 28000
C) 32000 D) 36000

Q2:
A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction?

A) 8 B) 9
C) 10 D) 11

Q3:
At what time between 5.30 and 6 will the hands of a clock be at right angles?

A) (43 + 5/11) min past 5 B) (43 + 7/11) min pats 5
C) 5                                 D) 7
 
Q4:
Insert the missing number.
16, 33, 65, 131, 261, (....)

A) 523 B) 521
C) 613 D) 721

Q5:
A room of 5m 44cm long and 3m 74cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor.

A) 136 B) 146
C) 166 D) 176

Q6:
If the cost price is 25% of the selling price. Then what is the profit percent?

A) 150% B) 200%
C) 300% D) 350%

Q7:
After replacing an old member with a new member, it was found that the average age of five members of a club is the same as it was 3 years ago. What is the difference between the ages of the replaced and the new member?

A) 12 B) 13
C) 14 D) 15

Q8:
If the product 4864*9 P 2 is divisible by 12, the value of p:

A) 1 B) 2
C) 3 D) 4

Q9:
If the simple interest on a sum of money at 5% per annum for 3 years is Rs. 1200, find the compound interest on the same sum for the same period at the same rate.

A) 1261 B) 1271
C) 1281 D) 1291

Q10:
The sum of all two-digit numbers divisible by 5 is

A) 945 B) 678
C) 439 D) 568

ANSWERS WITH EXPLANATION

Answer1: B) 28000
Explanation:

Suppose B invested Rs. x for y months. Then, A invested Rs. 3x for 2y months.
So, A : B = (3x * 2y) : (x * y) = 6xy : xy = 6 : 1.
B's profit: Total profit  = 1: 7.
Let the total profit be Rs. x Then,  1/7 = 4000/x  or x = 28000.

Answer2: B) 9
Explanation:

Actual price = Rs. (25 + 2.50) = Rs. 27.50. 
Saving = 2.50
Percentage Saving = [(2.50/27.50)*100]
= 2500/275
= 100/11%
≈9%

Answer3: B) (43 + 7/11) min pats 5
Explanation:

At 5 o'clock, the hands are 25 min. spaces apart.
To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces.
55 min. spaces are gained in 60 min
40 min. spaces are gained in 60/55×40 min 

Answer4: A) 523
Explanation:

Each number is twice the preceding one with 1 added or subtracted alternatively.
So, the next number is (2 x 261 + 1) = 523.

Answer5: D) 176
Explanation:

area of the room = 544 x 374 sq.cm
size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm
area of 1 tile = 34x34 sq cm
no. of tiles required = (544 x 374) / (34 x 34) = 176

Answer6: C) 300%
Explanation:

Let the S.P = 100
then C.P. = 25
Profit = 75
Profit% = (75/25) * 100 = 300%

Answer7: D) 15
Explanation:

i) Let the ages of the five members at present be a, b, c, d & e years. 
And the age of the new member is f years. 
ii) So the new average of five members' age = (a + b + c + d + f)/5 ------- (1) 
iii) Their corresponding ages 3 years ago = (a-3), (b-3), (c-3), (d-3) & (e-3) years 
So their average age 3 years ago = (a + b + c + d + e - 15)/5 = x ----- (2) 
==> a + b + c + d + e = 5x + 15 
==> a + b + c + d = 5x + 15 - e ------ (3) 
iv) Substituting this value of a + b + c + d = 5x + 15 - e in (1) above, 
The new average is: (5x + 15 - e + f)/5 
Equating this to the average age of x years, 3 yrs, ago as in (2) above, 
(5x + 15 - e + f)/5 = x 
==> (5x + 15 - e + f) = 5x 
Solving e - f = 15 years. 
Thus the difference of ages between replaced and new members = 15 years.

Answer8: A) 1
Explanation:

Clearly, 4864 is divisible by 4
So, 9 P 2 must be divisible by 3. So (9+P+2) must be divisible by 3.
So P=1.

Answer9: A) 1261
Explanation:

Clearly, Rate = 5% p.a., Time = 3 years, S.I.= Rs. 1200. . .
So principal=RS [100*1200]/3*5=RS 8000
Amount = Rs. 8000 x [1 +5/100]^3 - = Rs. 9261.
.. C.I. = Rs. (9261 - 8000) = Rs. 1261.

Answer10: A) 945
Explanation:

Required numbers are 10,15,20,25,...,95
This is an A.P. in which a=10,d=5, and l=95.
Let the number of terms in it be n. Then t=95
So a+(n-1)d=95.
10+(n-1)*5=95,then n=18.
Required sum=n/2(a+l)=18/2(10+95)=945.

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