## Quantitative Aptitude Questions and Answers With Explanation (Practice set 19)

**Q1:****A and B started a business jointly A's investment was thrice the investment of B and the period of his investment was two times the period of investment of B. If B received Rs. 4000 as profit, then their total profit is :**

A) 22000 B) 28000

C) 32000 D) 36000**Q2:****A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction?**

A) 8 B) 9

C) 10 D) 11**Q3:****At what time between 5.30 and 6 will the hands of a clock be at right angles?**

A) (43 + 5/11) min past 5 B) (43 + 7/11) min pats 5

C) 5 D) 7

**Q4:****Insert the missing number.****16, 33, 65, 131, 261, (....)**

A) 523 B) 521

C) 613 D) 721**Q5:****A room of 5m 44cm long and 3m 74cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor.**

A) 136 B) 146

C) 166 D) 176**Q6:****If the cost price is 25% of the selling price. Then what is the profit percent?**

A) 150% B) 200%

C) 300% D) 350%**Q7:****After replacing an old member with a new member, it was found that the average age of five members of a club is the same as it was 3 years ago. What is the difference between the ages of the replaced and the new member?**

A) 12 B) 13

C) 14 D) 15**Q8:****If the product 4864*9 P 2 is divisible by 12, the value of p:**

A) 1 B) 2

C) 3 D) 4**Q9:****If the simple interest on a sum of money at 5% per annum for 3 years is Rs. 1200, find the compound interest on the same sum for the same period at the same rate.**

A) 1261 B) 1271

C) 1281 D) 1291**Q10:****The sum of all two-digit numbers divisible by 5 is**

A) 945 B) 678

C) 439 D) 568

**ANSWERS WITH EXPLANATION**

**Answer1: B) 28000****Explanation:**

Suppose B invested Rs. x for y months. Then, A invested Rs. 3x for 2y months.

So, A : B = (3x * 2y) : (x * y) = 6xy : xy = 6 : 1.

B's profit: Total profit = 1: 7.

Let the total profit be Rs. x Then, 1/7 = 4000/x or x = 28000.**Answer2: B) 9****Explanation:**

Actual price = Rs. (25 + 2.50) = Rs. 27.50.

Saving = 2.50

Percentage Saving = [(2.50/27.50)*100]

= 2500/275

= 100/11%

≈9%**Answer3: B) (43 + 7/11) min pats 5****Explanation:**

At 5 o'clock, the hands are 25 min. spaces apart.

To be at right angles and that too between 5.30 and 6, the minute hand has to gain (25 + 15) = 40 min. spaces.

55 min. spaces are gained in 60 min

40 min. spaces are gained in 60/55×40 min **Answer4: A) 523****Explanation:**

Each number is twice the preceding one with 1 added or subtracted alternatively.

So, the next number is (2 x 261 + 1) = 523.**Answer5: D) 176****Explanation:**

area of the room = 544 x 374 sq.cm

size of largest square tile = H.C.F of 544cm and 374 cm= 34 cm

area of 1 tile = 34x34 sq cm

no. of tiles required = (544 x 374) / (34 x 34) = 176**Answer6: C) 300%****Explanation:**

Let the S.P = 100

then C.P. = 25

Profit = 75

Profit% = (75/25) * 100 = 300%**Answer7: D) 15****Explanation:**

i) Let the ages of the five members at present be a, b, c, d & e years.

And the age of the new member is f years.

ii) So the new average of five members' age = (a + b + c + d + f)/5 ------- (1)

iii) Their corresponding ages 3 years ago = (a-3), (b-3), (c-3), (d-3) & (e-3) years

So their average age 3 years ago = (a + b + c + d + e - 15)/5 = x ----- (2)

==> a + b + c + d + e = 5x + 15

==> a + b + c + d = 5x + 15 - e ------ (3)

iv) Substituting this value of a + b + c + d = 5x + 15 - e in (1) above,

The new average is: (5x + 15 - e + f)/5

Equating this to the average age of x years, 3 yrs, ago as in (2) above,

(5x + 15 - e + f)/5 = x

==> (5x + 15 - e + f) = 5x

Solving e - f = 15 years.

Thus the difference of ages between replaced and new members = 15 years.**Answer8: A) 1****Explanation:**

Clearly, 4864 is divisible by 4

So, 9 P 2 must be divisible by 3. So (9+P+2) must be divisible by 3.

So P=1.**Answer9: A) 1261****Explanation:**

Clearly, Rate = 5% p.a., Time = 3 years, S.I.= Rs. 1200. . .

So principal=RS [100*1200]/3*5=RS 8000

Amount = Rs. 8000 x [1 +5/100]^3 - = Rs. 9261.

.. C.I. = Rs. (9261 - 8000) = Rs. 1261.**Answer10: A) 945****Explanation:**

Required numbers are 10,15,20,25,...,95

This is an A.P. in which a=10,d=5, and l=95.

Let the number of terms in it be n. Then t=95

So a+(n-1)d=95.

10+(n-1)*5=95,then n=18.

Required sum=n/2(a+l)=18/2(10+95)=945.

**Also Practice:**** ****Quantitative Aptitude Questions and Answers With Explanation (Practice set 18)**