Quantitative Aptitude Questions and Answers With Explanation (Practice set 9)

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Q1:
A clock is set right at 5 a.m. The clock loses 16 minutes in 24 hours. What will be the true time when the clock indicates 10 p.m. on the 4th day?

A) 11:00pm B) 12:00pm
C) 1:00pm   D) 2:00pm

Q2:
Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?

A) 10 min. 20 sec. B) 11 min. 45 sec.
C) 12 min. 30 sec. D) 14 min. 40 sec.

Q3:
A sum of Rs.312 was divided among 100 boys and girls in such a way that the boy gets Rs.3.60 and each girl Rs. 2.40 the number of girls is

A) 35 B) 40
C) 45 D) 50

Q4:
P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8 days working 10 hours a day. If both p and Q work together, working 8 hours a day, in how many days can they complete the work?

A) 60/11 B) 61/11
C) 71/11 D) 72/11

Q5:
By selling 45 lemons for Rs 40, a man loses 20%. How many should he sell for Rs 24 to gain 20% in the transaction?

A) 16 B) 18
C) 20 D) 22

Q6:
At what rate percent per annum will a sum of money double in 8 years.

A) 12.5% B) 13.5%
C) 11.5% D) 14.5%

Q7:
Find the odd man out?
396, 462, 572, 427, 671, 264.

A) 671 B) 462
C) 427 D) 264

Q8:
If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to:

A) 55/601 B) 601/55
C) 11/120 D) 120/11

Q9:
A sum of money amounts to Rs.6690 after 3 years and to Rs.10,035 after 6 years on compound interest. find the sum.

A) 4360 B) 4460
C) 4560 D) 4660

Q10:
Insert the missing number.
8, 7, 11, 12, 14, 17, 17, 22, (....)

A) 20 B) 22
C) 24 D) 27

 

ANSWERS WITH EXPLANATIONS

 

Answer1: A) 11pm
Explanation:
Time from 5 am. on a day to 10 pm. on 4th day = 89 hours.
Now 23 hrs 44 min. of this clock = 24 hours of the correct clock.
356/15 hrs of this clock = 24 hours of correct clock
89 hrs of this clock = (24 x 31556 x 89) hrs of correct clock.
= 90 hrs of the correct clock.
So, the correct time is 11 p.m.

Answer2: D) 14 min. 40 sec.
Explanation:
Part filled in 4 minutes =4(1/15+1/20) = 7/15
Remaining part =(1-7/15) = 8/15
Part filled by B in 1 minute =1/20 : 8/15 :: 1:x 
x = (8/15*1*20) = (10+2/3)min = 10min 40sec
The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec

Answer3: B) 40
Explanation:
Step (i): Let x be the number of boys and y be the number of girls.
Given the total number of boys and girls = 100
x+y=100 -------------- (i)
Step (ii): A boy gets Rs. 3.60 and a girl gets Rs. 2.40
The amount is given to 100 boys and girls = Rs. 312
3.60x + 2.40y = 312 -------------- (ii)
Step (iii):
Solving (i) and (ii)
3.60x + 3.60y = 360 --------- Multiply (i) by 3.60
3.60x + 2.40y = 312 --------- (ii)
1.20y = 48
y = 48 / 1.20
= 40

Answer4: A) 60/11
Explanation:
P can complete the work in (12 x 8) hrs = 96 hrs 
Q can complete the work in (8 x 10) hrs=80 hrs 
Therefore, P's 1 hour work=1/96   and Q's 1 hour work= 1/80
(P+Q)'s 1 hour's work =(1/96) + (1/80) = 11/480. So both P and Q will finish the work in 480/11 hrs  
Therefore, Number of days of 8 hours each = (480/11) x (1/8) = 60/11

Answer5: B) 18
Explanation:
Let S.P. of 45 lemons be Rs. x.
Then, 80 : 40 = 120 : x or   x = 40×12080= 60
For Rs.60, lemons sold = 45
For Rs.24, lemons sold  =4560×24= 18.

Answer6: A) 12.5%
Explanation:
Let principal = P, Then, S.I.= P and Time = 8 years
We know that S.I. = PTR/100
Rate = [(100 x P)/ (P x 8)]% = 12.5% per annum.   

Answer7: C) 427
Explanation:
Here the given series is 396, 462, 572, 427, 671, 264.
In all the terms, the middle digit is the sum of the first and third digit except 427.
So the Odd number in the given series is 427.

Answer8: C) 11/120
Explanation:
Let the numbers be a and b.
Then, a + b = 55 and ab = 5 x 120 = 600.
The required sum =1/a+1/b = a+b/ab= 55/600=11/120   

Answer9: B) 4460
Explanation:
Let the sum be Rs.P.then
P(1+R/100)^3=6690…(i) and P(1+R/100)^6=10035…(ii)
On dividing, we get (1+R/100)^3=10025/6690=3/2.
Substituting this value in (I), we get:
P*(3/2)=6690 or P=(6690*2/3)=4460
Hence, the sum is rs.4460.

Answer10: A) 20
Explanation:
There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.

 

Also Practice: Quantitative Aptitude Questions and Answers With Explanation (Practice set 8)

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