Quantitative Aptitude Questions and Answers With Explanation (Practice set 8)

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Q1:
In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 130 marks, the no of questions he attempts correctly is :

A) 35                                                                                         B) 38
C) 40                                                                                         D) 42

Q2:
A, B, C started a business with their investments in the ratio 1:3:5. After 4 months, A invested the same amount as before and B, as well as C, withdrew half of their investments. The ratio of their profits at the end of the year is :

A) 1 : 2 : 3                                                                                B) 3 : 4 : 15
C) 3 : 5 : 10                                                                              D) 5 : 6 : 10

Q3: 
At what time between 2 and 3 o'clock will the hands of a clock be together?

A) (9 + 10/11) min past 2                                                        B) (10 + 10/11) min past 2
C) (11 + 10/11) min past 2                                                      D) (12 + 10/11) min past 2

Q4:
What was the day of the week on, 16th July 1776?

A) Tuesday                                                                              B) Wednesday
C) Monday                                                                              D) Saturday

Q5:
Two dice are tossed. The probability that a total score is a prime number is:

A) 5/12                                                                                  B) 1/6
C) 1/2                                                                                    D) 7/9

Q6:
The average of 7 consecutive numbers is 20. The largest of these numbers is :

A) 21                                                                                   B) 22
C) 23                                                                                   D) 24

Q7: 
What was the day of the week on 28th May 2006?

A) Sunday                                                                        B) Friday
C) Wednesday                                                                  D) Tuesday

Q8:
The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?

A) 0                                                                                B) -1
C) 1                                                                                D) none of these

Q9:
In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:

A) 5.4m                                                                       B) 4.5m
C) 5m                                                                           D) 6m

Q10:
If the diagonal of a rectangle is 17cm long and its perimeter is 46 cm. Find the area of the rectangle.

A) 110                                                                       B) 120
C) 130                                                                       D) 140


ANSWERS WITH EXPLANATION

Answer1: B) 38
Explanation:
Let the number of correct answers be X.
A number of incorrect answers = (60 – X).
4x – (60 – x) = 130
=> 5x = 190 
=> x = 38

Answer2: D) 5: 6: 10
Explanation:
Let their initial investments be x, 3x, and 5x respectively. Then,
A:B:C = (x*4+2x*8) : (3x*4+(3x/2)*8) : (5x*4+(5x/2)*8)
20x : 24x : 40x = 5 : 6 : 10

Answer3: B) (10 + 10/11) min past 2
Explanation:
At 2 o'clock, the hour hand is at 2 and the minute hand is at 12, i.e. they are 10 min spaces apart. 
To be together, the minute hand must gain 10 minutes over the hour hand. 
Now, 55 minutes are gained by it in 60 min
10 minutes will be gained in 60/55 x 10min. = (10 + 10/11)
The hands will coincide at (10 + 10/11) min past 2

Answer4: A) Tuesday
Explanation:
16th July 1776 = (1775 years + Period from 1st Jan 1776 to 16th July 1776)
Counting of odd days :
1600 years have 0 odd days.
100 years have 5 odd days.
75 years = (18 leap years + 57 ordinary years) =  [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day. 
Jan   Feb   Mar   Apr   May   Jun   Jul  
31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days) 
Total number of odd days = (0 + 2) = 2.  
The required day was 'Tuesday'

Answer5: A) 5/12
Explanation:
Clearly, n(S) = (6 x 6) = 36.
Let E = Event that a sum is a prime number.
Then E= { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4,3),(5, 2), (5, 6), (6, 1), (6, 5) }
n(E) = 15.
P(E) = n(E)/n(S) = 15/36 = 5/12.

Answer6: C) 23
Explanation:
Let the numbers be x, x + 1, x + 2,  x + 3, x + 4, x + 5 and x + 6,
Then   (x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6)) / 7 = 20.
or  7x + 21 = 140 or 7x = 119 or x =17.
Latest number = x + 6 = 23

Answer7: A) Sunday
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) = 6 odd days
(31[jan] + 28 [Feb]+ 31[Mar] + 30[April] + 28[May] ) = 148 dayss = (21 weeks + 1 day) = 1 odd day.
Total number of odd days = (0 +

0 + 6 + 1) = 7 = 0 odd days.
Given day is Sunday

Answer8: A) 0
Explanation:
Average of 20 numbers = 0. 
Sum of 20 numbers = (0 * 20) = 0. 
It is quite possible that 19 of these numbers may be positive and if their sum is a, then the 20th number is (- a)

Answer9: D) 6m
Explanation:
A : B = 100 : 90.
A : C = 100 : 87.
B/C = (B/A*A/C) = (90/100*100/87) = 30/29
When B runs 30 m, C runs 29 m.
When B runs 180 m, C runs (29/30*180)m =174m
B beats C by (180 - 174) m = 6 m

Answer10: B) 120
Explanation:
let length = x and breadth = y then  
2(x+y) = 46         =>   x+y = 23  
x²+y² = 17² = 289  
now (x+y)² = 23² 
=> x²+y²+2xy= 529 
=> 289+ 2xy = 529
=> xy = 120  
area = xy = 120 sq.cm

Also practice:

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10 Math Tricks To Do Math Faster (Practice set 4)

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Quantitative Aptitude Question And Answer With Explanation (Practice set 6)

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