## Quantitative Aptitude Questions and Answers With Explanation (Practice set 17)

By Sahil Bansal | Views: 551 Q1:
If the letters of the word SACHIN are arranged in all possible ways and these words are written out as in a dictionary, then the word ‘SACHIN’ appears at the serial number :

A) 601 B) 600
C) 603 D) 602

Q2:
A college has 10 basketball players. A 5-member team and a captain will be selected out of these 10 players. How many different selections can be made?

A) 1260 B) 1400
C) 1250 D) 1600

Q3:
Find the compound interest on Rs. 7500 at 4% per annum for 2 years, compounded annually.

A) 612 B) 712
C) 812 D) 912

Q4:
How many weekends in a year?

A) 52 B) 53
C) 103 D) 104

Q5:
What percent of 7.2 kg is 18 gms?

A) .25% B) .5%
C) .75% D) 1%

Q6:
Find the Odd One Out?
4, 6, 12, 30, 81, 315.

A) 6 B) 12
C) 81 D) 315

Q7:
What is the probability of getting a sum of 9 from two throws of a dice?

A) 1/2 B) 3/4
C) 1/9 D) 2/9

Q8:
A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is :

A) 285 B) 290
C) 297 D) 305

Q9:
The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?

A) 12 B) 13
C) 14 D) 15

Q10:
A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be

A) 7744 B) 8844
C) 5544 D) 4444

Explanation:

If the word started with the letter A then the remaining 5 positions can be filled in  5! Ways.
If it started with c then the remaining 5 positions can be filled in 5! Ways. Similarly, if it started with H, I, N the remaining 5 positions can be filled in 5! Ways.
If it started with S then the remaining position can be filled with A, C, H, I, N in alphabetical order as in a dictionary.
The required word SACHIN can be obtained after the 5X5!=600 Ways i.e. SACHIN is the 601st letter.

Explanation:

A team of 6 members has to be selected from the 10 players. This can be done in 10C6 or 210 ways.
Now, the captain can be selected from these 6 players in 6 ways.
Therefore, the total ways the selection can be made is 210×6= 1260

Explanation:

Amount = Rs [7500*(1+(4/100)2] = Rs (7500 * (26/25) * (26/25) ) = Rs. 8112.
therefore, C.I. = Rs. (8112 - 7500) = Rs. 612.

Explanation:

Weekend means Saturday & Sunday together. In total, we have 52 weeks in a year. So there are 52 weekends in a year.
In normal we have 104 Weekend Days.
We know that Each normal year has 365 days or 52 weeks plus one day, and each week has two weekend days, which means there are approximately 104 weekend days each year.
Whereas in a leap year we have 366 days it adds one more day to the year. And what makes the change is the starting day of the year.

Explanation:

Required percentage = (18/7200 * 100)% =  1/4% = 0.25%

Explanation:

Given the number, series is 4, 6, 12, 30, 81, 315.
Here it follows a pattern that
4
4 x 1.5 = 6
6 x 2 = 12
12 x 2.5 = 30
30 x 3 = 90 not equals to 81
90 x 3.5 = 315
Hence the odd one in the series is 81.

Explanation:
In two throws of a die, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E) =n(E)/n(S)=4/36=1/9.

Explanation:

Since the month begins with a Sunday, so there will be five Sundays in the month,
Required average = (510 * 5 + 240 * 25) / 30 = 8550/30 = 285.

Explanation:

(A+B) - (B+C) = 12
A - C = 12.
C is younger than A by 12 years.